2.I.1DDifferential EquationsPart IA, 2002Solve the equationy¨+y˙−2y=e−t\ddot{y}+\dot{y}-2 y=e^{-t}y¨+y˙−2y=e−tsubject to the conditions y(t)=y˙(t)=0y(t)=\dot{y}(t)=0y(t)=y˙(t)=0 at t=0t=0t=0. Solve the equationy¨+y˙−2y=et\ddot{y}+\dot{y}-2 y=e^{t}y¨+y˙−2y=etsubject to the same conditions y(t)=y˙(t)=0y(t)=\dot{y}(t)=0y(t)=y˙(t)=0 at t=0t=0t=0.