Two solutions of the recurrence relation
xn+2+b(n)xn+1+c(n)xn=0
are given as pn and qn, and their Wronskian is defined to be
Wn=pnqn+1−pn+1qn
Show that
Wn+1=W1m=1∏nc(m)
Suppose that b(n)=α, where α is a real constant lying in the range [−2,2], and that c(n)=1. Show that two solutions are xn=einθ and xn=e−inθ, where cosθ=−α/2. Evaluate the Wronskian of these two solutions and verify (∗).