(i) Consider the equation
∂t∂u+∂x∂u=∂x2∂2u+f(t,x)
and, using the change of variables (t,x)↦(s,y)=(t,x−t), show that it can be transformed into an equation of the form
∂s∂U=∂y2∂2U+F(s,y)
where U(s,y)=u(s,y+s) and you should determine F(s,y).
(ii) Let H(y) be the Heaviside function. Find the general continuously differentiable solution of the equation
w′′(y)+H(y)=0
(iii) Using (i) and (ii), find a continuously differentiable solution of
∂t∂u+∂x∂u=∂x2∂2u+H(x−t)
such that u(t,x)→0 as x→−∞ and u(t,x)→−∞ as x→+∞