Paper 2, Section II, ADifferential EquationsPart IA, 2012Find the solution to the system of equationsdxdt+−4x+2yt=−9,dydt+x−5yt=3\begin{gathered} \frac{d x}{d t}+\frac{-4 x+2 y}{t}=-9, \\ \frac{d y}{d t}+\frac{x-5 y}{t}=3 \end{gathered}dtdx+t−4x+2y=−9,dtdy+tx−5y=3in t⩾1t \geqslant 1t⩾1 subject tox=0 and y=0 at t=1x=0 \quad \text { and } \quad y=0 \quad \text { at } \quad t=1x=0 and y=0 at t=1[Hint: powers of t.]