Consider the second-order differential equation for y(t) in t⩾0
y¨+2ky˙+(k2+ω2)y=f(t).
(i) For f(t)=0, find the general solution y1(t) of (∗).
(ii) For f(t)=δ(t−a) with a>0, find the solution y2(t,a) of (∗) that satisfies y=0 and y˙=0 at t=0.
(iii) For f(t)=H(t−b) with b>0, find the solution y3(t,b) of (∗) that satisfies y=0 and y˙=0 at t=0.
(iv) Show that
y2(t,b)=−∂b∂y3