(i) An inertial frame S has orthonormal coordinate basis vectors e1,e2,e3. A second frame S′ rotates with angular velocity ω relative to S and has coordinate basis vectors e1′,e2′,e3′. The motion of S′ is characterised by the equations dei′/dt=ω×ei′ and at t=0 the two coordinate frames coincide.
If a particle P has position vector r show that v=v′+ω×r where v and v′ are the velocity vectors of P as seen by observers fixed respectively in S and S′.
(ii) For the remainder of this question you may assume that a=a′+2ω×v′+ω×(ω×r) where a and a′ are the acceleration vectors of P as seen by observers fixed respectively in S and S′, and that ω is constant.
Consider again the frames S and S′ in (i). Suppose that ω=ωe3 with ω constant. A particle of mass m moves under a force F=−4mω2r. When viewed in S′ its position and velocity at time t=0 are (x′,y′,z′)=(1,0,0) and (x˙′,y˙′,z˙′)=(0,0,0). Find the motion of the particle in the coordinates of S′. Show that for an observer fixed in S′, the particle achieves its maximum speed at time t=π/(4ω) and determine that speed. [Hint: you may find it useful to consider the combination ζ=x′+iy′.]