(a) Let y1(x) be a solution of the equation
dx2d2y+p(x)dxdy+q(x)y=0
Assuming that the second linearly independent solution takes the form y2(x)= v(x)y1(x), derive an ordinary differential equation for v(x).
(b) Consider the equation
(1−x2)dx2d2y−2xdxdy+2y=0,−1<x<1.
By inspection or otherwise, find an explicit solution of this equation. Use the result in (a) to find the solution y(x) satisfying the conditions
y(0)=dxdy(0)=1