Use the transformation
y(t)=cx(t)1dtdx(t)
where c is a constant, to map the Ricatti equation
dtdy+cy2+a(t)y+b(t)=0,t>0
to a linear equation.
Using the above result, as well as the change of variables τ=lnt, solve the boundary value problem
dtdy+y2+ty−t2λ2=0,t>0y(1)=2λ
where λ is a positive constant. What is the value of t>0 for which the solution is singular?