Show that for each t>0 and x∈R the function
K(x,t)=4πt1exp(−4tx2)
satisfies the heat equation
∂t∂u=∂x2∂2u
For t>0 and x∈R define the function u=u(x,t) by the integral
u(x,t)=∫−∞∞K(x−y,t)f(y)dy
Show that u satisfies the heat equation and limt→0+u(x,t)=f(x). [Hint: You may find it helpful to consider the substitution Y=(x−y)/4t.]
Burgers' equation is
∂t∂w+w∂x∂w=∂x2∂2w
By considering the transformation
w(x,t)=−2u1∂x∂u
solve Burgers' equation with the initial condition limt→0+w(x,t)=g(x).