If B is a vector, and
Tij=αBiBj+βBkBkδij
show for arbitrary scalars α and β that Tij is a symmetric second-rank tensor.
Find the eigenvalues and eigenvectors of Tij.
Suppose now that B depends upon position x and that ∇⋅B=0. Find constants α and β such that
∂xj∂Tij=[(∇×B)×B]i.
Hence or otherwise show that if B vanishes everywhere on a surface S that encloses a volume V then
∫V(∇×B)×BdV=0