The equation governing small amplitude waves on a string can be written as
∂t2∂2y=∂x2∂2y
The end points x=0 and x=1 are fixed at y=0. At t=0, the string is held stationary in the waveform,
y(x,0)=x(1−x) in 0≤x≤1.
The string is then released. Find y(x,t) in the subsequent motion.
Given that the energy
∫01[(∂t∂y)2+(∂x∂y)2]dx
is constant in time, show that
n odd n⩾1∑n41=96π4