Show that general, regular axisymmetric solutions ψ(r,θ) to the equation ∇2ψ=0 are given by
ψ(r,θ)=n=0∑∞(Anrn+Bnr−(n+1))Pn(cosθ)
where An,Bn are constants and Pn are the Legendre polynomials. [You may use without proof that regular solutions to Legendre's equation −dxd[(1−x2)dxdy(x)]=λy(x) are given by Pn(x) with λ=n(n+1) and non-negative integer n.]
(ii) Consider a uniformly charged wire in the form of a ring of infinitesimal width with radius r0=1 and a constant charge per unit length σ. By Coulomb's law, the electric potential due to a point charge q at a point a distance d from the charge is
U=4πϵ0dq
where ϵ0 is a constant. Let the z-axis be perpendicular to the circle and pass through the circle's centre (see figure). Show that the potential due to the charged ring at a point on the z-axis at location z is given by
V=2ϵ01+z2σ.
(iii) The potential V generated by the charged ring of (ii) at arbitrary points (excluding points directly on the ring which can be ignored for this question) is determined by Laplace's equation ∇2V=0. Calculate this potential with the boundary condition limr→∞V=0, where r=x2+y2+z2. [You may use without proof that
1+x21=m=0∑∞x2m(−1)m22m(m!)2(2m)!
for ∣x∣<1. Furthermore, the Legendre polynomials are normalized such that Pn(1)=1.]