(a) Carefully state the Picard-Lindelöf theorem on solutions to ordinary differential equations.
(b) Let X=C([1,b],Rn) be the set of continuous functions from a closed interval [1,b] to Rn, and let ∥⋅∥ be a norm on Rn.
(i) Let f∈X. Show that for any c∈[0,∞) the norm
∥f∥c=t∈[1,b]sup∥∥∥f(t)t−c∥∥∥
is Lipschitz equivalent to the usual sup norm on X.
(ii) Assume that F:[1,b]×Rn→Rn is continuous and Lipschitz in the second variable, i.e. there exists M>0 such that
∥F(t,x)−F(t,y)∥⩽M∥x−y∥
for all t∈[1,b] and all x,y∈Rn. Define φ:X→X by
φ(f)(t)=∫1tF(l,f(l))dl
for t∈[1,b].
Show that there is a choice of c such that φ is a contraction on (X,∥⋅∥c). Deduce that for any y0∈Rn, the differential equation
Df(t)=F(t,f(t))
has a unique solution on [1,b] with f(1)=y0.