A1.18

Transport Processes
Part II, 2003

(i) A solute occupying a domain V0V_{0} has concentration C(x,t)C(\boldsymbol{x}, t) and is created at a rate S(x,t)S(\boldsymbol{x}, t) per unit volume; J(x,t)\boldsymbol{J}(\boldsymbol{x}, t) is the flux of solute per unit area; x,t\boldsymbol{x}, t are position and time. Derive the transport equation

Ct+J=SC_{t}+\nabla \cdot \boldsymbol{J}=S

State Fick's Law of diffusion and hence write down the diffusion equation for C(x,t)C(\boldsymbol{x}, t) for a case in which the solute flux occurs solely by diffusion, with diffusivity D(x)D(\boldsymbol{x}).

In a finite domain 0xL,D,S0 \leqslant x \leqslant L, D, S and the steady-state distribution of CC depend only on x;Cx ; C is equal to C0C_{0} at x=0x=0 and C1C0C_{1} \neq C_{0} at x=Lx=L. Find C(x)C(x) in the following two cases: (a) D=D0,S=0D=D_{0}, S=0, (b) D=D1x1/2,S=0D=D_{1} x^{1 / 2}, S=0,

where D0D_{0} and D1D_{1} are positive constants.

Show that there is no steady solution satisfying the boundary conditions if D=D= D1x,S=0.D_{1} x, S=0 .

(ii) For the problem of Part (i), consider the case D=D0,S=kCD=D_{0}, S=k C, where D0D_{0} and kk are positive constants. Calculate the steady-state solution, C=Cs(x)C=C_{s}(x), assuming that k/D0nπ/L\sqrt{k / D_{0}} \neq n \pi / L for any integer nn.

Now let

C(x,0)=C0sinα(Lx)sinαLC(x, 0)=C_{0} \frac{\sin \alpha(L-x)}{\sin \alpha L}

where α=k/D0\alpha=\sqrt{k / D_{0}}. Find the equations, boundary and initial conditions satisfied by C(x,t)=C(x,t)Cs(x)C^{\prime}(x, t)=C(x, t)-C_{s}(x). Solve the problem using separation of variables and show that

C(x,t)=n=1AnsinnπxLexp[(α2n2π2L2)D0t]C^{\prime}(x, t)=\sum_{n=1}^{\infty} A_{n} \sin \frac{n \pi x}{L} \exp \left[\left(\alpha^{2}-\frac{n^{2} \pi^{2}}{L^{2}}\right) D_{0} t\right]

for some constants AnA_{n}. Write down an integral expression for AnA_{n}, show that

A1=2πC1α2L2π2,A_{1}=-\frac{2 \pi C_{1}}{\alpha^{2} L^{2}-\pi^{2}},

and comment on the behaviour of the solution for large times in the two cases αL<π\alpha L<\pi and αL>π\alpha L>\pi.