A shallow layer of fluid of viscosity μ, density ρ and depth h(x,t) lies on a rigid horizontal plane y=0 and is bounded by impermeable barriers at x=−L and x=L (L≫h). Gravity acts vertically and a wind above the layer causes a shear stress τ(x) to be exerted on the upper surface in the +x direction. Surface tension is negligible compared to gravity.
(a) Assuming that the steady flow in the layer can be analysed using lubrication theory, show that the horizontal pressure gradient px is given by px=ρghx and hence that
hhx=23ρgτ.
Show also that the fluid velocity at the surface y=h is equal to τh/4μ, and sketch the velocity profile for 0⩽y⩽h.
(b) In the case in which τ is a constant, τ0, and assuming that the difference between h and its average value h0 remains small compared with h0, show that
h≈h0(1+2ρgh023τ0x)
provided that
ρgh02τ0L≪1
(c) Surfactant at surface concentration Γ(x) is added to the surface, so that now
τ=τ0−AΓx,
where A is a positive constant. The surfactant is advected by the surface fluid velocity and also experiences a surface diffusion with diffusivity D. Write down the equation for conservation of surfactant, and hence show that
(τ0−AΓx)hΓ=4μDΓx
From equations (1), (2) and (3) deduce that
Γ0Γ=exp[18μDρg(h3−h03)]
where Γ0 is a constant. Assuming once more that h1≡h−h0≪h0, and that h=h0 at x=0, show further that
h1≈2ρgh03τ0x[1+4μDAΓ0h0]−1
provided that
μDτ0h0L≪1 as well as ρgh02τ0L≪1