3.II.14A

Further Complex Methods
Part II, 2005

Show that the equation

zw+2kw+zw=0,z w^{\prime \prime}+2 k w^{\prime}+z w=0,

where kk is constant, has solutions of the form

w(z)=γ(t2+1)k1eztdtw(z)=\int_{\gamma}\left(t^{2}+1\right)^{k-1} e^{z t} d t

provided that the path γ\gamma is chosen so that [(t2+1)kezt]γ=0\left[\left(t^{2}+1\right)^{k} e^{z t}\right]_{\gamma}=0.

(i) In the case Re k>0k>0, show that there is a choice of γ\gamma for which w(0)=iB(k,12)w(0)=i B\left(k, \frac{1}{2}\right).

(ii) In the case k=n/2k=n / 2, where nn is any integer, show that γ\gamma can be a finite contour and that the corresponding solution satisfies w(0)=0w(0)=0 if n1n \leqslant-1.