4.II.15D
For an ideal gas of bosons, the average occupation number can be expressed as
where has been included to account for the degeneracy of the energy level . In the approximation in which a discrete set of energies is replaced with a continuous set with momentum , the density of one-particle states with momentum in the range to is . Explain briefly why
where is the volume of the gas. Using this formula with equation , obtain an expression for the total energy density of an ultra-relativistic gas of bosons at zero chemical potential as an integral over . Hence show that
where is a number you should find. Why does this formula apply to photons?
Prior to a time years, the universe was filled with a gas of photons and non-relativistic free electrons and protons. Subsequently, at around years, the protons and electrons began combining to form neutral hydrogen,
Deduce Saha's equation for this recombination process stating clearly the steps required:
where is the ionization energy of hydrogen. [Note that the equilibrium number density of a non-relativistic species is given by , while the photon number density is , where
Consider now the fractional ionization , where is the baryon number of the universe and is the baryon-to-photon ratio. Find an expression for the ratio
in terms only of and constants such as and . One might expect neutral hydrogen to form at a temperature given by , but instead in our universe it forms at the much lower temperature . Briefly explain why.