Paper 1, Section I, D

Cosmology
Part II, 2009

Prior to a time t100,000t \sim 100,000 years, the Universe was filled with a gas of photons and non-relativistic free electrons and protons maintained in equilibrium by Thomson scattering. At around t400,000t \sim 400,000 years, the protons and electrons began combining to form neutral hydrogen,

p+eH+γp+e^{-} \leftrightarrow H+\gamma

[You may assume that the equilibrium number density of a non-relativistic species (kTmc2)\left(k T \ll m c^{2}\right) is given by

n=gs(2πmkTh2)3/2exp((μmc2)/kT)n=g_{s}\left(\frac{2 \pi m k T}{h^{2}}\right)^{3 / 2} \exp \left(\left(\mu-m c^{2}\right) / k T\right)

while the photon number density is

nγ=16πζ(3)(kThc)3,(ζ(3)1.20)n_{\gamma}=16 \pi \zeta(3)\left(\frac{k T}{h c}\right)^{3}, \quad(\zeta(3) \approx 1.20 \ldots)

Deduce Saha's equation for the recombination process ()(*) stating clearly your assumptions and the steps made in the calculation,

ne2nH=(2πmekTh2)3/2exp(I/kT)\frac{n_{e}^{2}}{n_{H}}=\left(\frac{2 \pi m_{e} k T}{h^{2}}\right)^{3 / 2} \exp (-I / k T)

where II is the ionization energy of hydrogen.

Consider now the fractional ionization Xe=ne/nBX_{e}=n_{e} / n_{B} where nB=np+nH=ηnγn_{B}=n_{p}+n_{H}=\eta n_{\gamma} is the baryon number of the Universe and η\eta is the baryon to photon ratio. Find an expression for the ratio

(1Xe)/Xe2\left(1-X_{e}\right) / X_{e}^{2}

in terms only of kTk T and constants such as η\eta and II.

Suggest a reason why neutral hydrogen forms at a temperature kT0.3eVk T \approx 0.3 \mathrm{eV} which is much lower than the hydrogen ionization temperature kT=I13eVk T=I \approx 13 \mathrm{eV}.