Paper 3, Section II, E

Fluid Dynamics II
Part II, 2015

Consider a three-dimensional high-Reynolds number jet without swirl induced by a force F=Fez\mathbf{F}=F \mathbf{e}_{z} imposed at the origin in a fluid at rest. The velocity in the jet, described using cylindrical coordinates (r,θ,z)(r, \theta, z), is assumed to remain steady and axisymmetric, and described by a boundary layer analysis.

(i) Explain briefly why the flow in the jet can be described by the boundary layer equations

uruzr+uzuzz=ν1rr(ruzr)u_{r} \frac{\partial u_{z}}{\partial r}+u_{z} \frac{\partial u_{z}}{\partial z}=\nu \frac{1}{r} \frac{\partial}{\partial r}\left(r \frac{\partial u_{z}}{\partial r}\right)

(ii) Show that the momentum flux in the jet, F=Sρuz2dSF=\int_{S} \rho u_{z}^{2} d S, where SS is an infinite surface perpendicular to ez\mathbf{e}_{z}, is not a function of zz. Combining this result with scalings from the boundary layer equations, derive the scalings for the unknown width δ(z)\delta(z) and typical velocity U(z)U(z) of the jet as functions of zz and the other parameters of the problem (ρ,ν,F)(\rho, \nu, F).

(iii) Solving for the flow using a self-similar Stokes streamfunction

ψ(r,z)=U(z)δ2(z)f(η),η=r/δ(z)\psi(r, z)=U(z) \delta^{2}(z) f(\eta), \quad \eta=r / \delta(z)

show that f(η)f(\eta) satisfies the differential equation

ffη(f2+ff)=fηf+η2f.f f^{\prime}-\eta\left(f^{\prime 2}+f f^{\prime \prime}\right)=f^{\prime}-\eta f^{\prime \prime}+\eta^{2} f^{\prime \prime \prime} .

What boundary conditions should be applied to this equation? Give physical reasons for them.

[Hint: In cylindrical coordinates for axisymmetric incompressible flow (ur(r,z),0,uz(r,z))\left(u_{r}(r, z), 0, u_{z}(r, z)\right) you are given the incompressibility condition as

1rr(rur)+uzz=0\frac{1}{r} \frac{\partial}{\partial r}\left(r u_{r}\right)+\frac{\partial u_{z}}{\partial z}=0

the zz-component of the Navier-Stokes equation as

ρ(uzt+uruzr+uzuzz)=pz+μ[1rr(ruzr)+2uzz2]\rho\left(\frac{\partial u_{z}}{\partial t}+u_{r} \frac{\partial u_{z}}{\partial r}+u_{z} \frac{\partial u_{z}}{\partial z}\right)=-\frac{\partial p}{\partial z}+\mu\left[\frac{1}{r} \frac{\partial}{\partial r}\left(r \frac{\partial u_{z}}{\partial r}\right)+\frac{\partial^{2} u_{z}}{\partial z^{2}}\right]

and the relationship between the Stokes streamfunction, ψ(r,z)\psi(r, z), and the velocity components as

ur=1rψz,uz=1rψr]\left.u_{r}=-\frac{1}{r} \frac{\partial \psi}{\partial z}, \quad u_{z}=\frac{1}{r} \frac{\partial \psi}{\partial r}\right]